Question

A car starts from rest and attains a velocity of 30m/s in 2 sec . calculate accteration and distance covered answer ​

Answer 1

Answer:

15 and 60

Explanation:

a= change in velocity / change in time

change in velocity = u-v = 0-30= -30

change in time= 0-2= -2

and  now acceleration =  (-30)/(-2)

                                    = 15m/s^2

now distance = speed x time

                     = 30x2 = 60m