A car starts from rest and attains a velocity of 40m/s in 20s. It maintains this velocity for 30s and then comes to rest in 25s.
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For this, we can use:
d=v1+v2/2 * t
The car starts from rest, thus, v1=0. So:
d=20/2 m/s x 5 sec
=50m
20/5=4 m/s²
400=0+2 x 4 x s
For this, we can use:
d=v1+v2/2 * t
The car starts from rest, thus, v1=0. So:
d=20/2 m/s x 5 sec
=50m
20/5=4 m/s²
400=0+2 x 4 x s
mark me as brainlist answer
d=v1+v2/2 * t
The car starts from rest, thus, v1=0. So:
d=20/2 m/s x 5 sec
=50m
20/5=4 m/s²
400=0+2 x 4 x s
For this, we can use:
d=v1+v2/2 * t
The car starts from rest, thus, v1=0. So:
d=20/2 m/s x 5 sec
=50m
20/5=4 m/s²
400=0+2 x 4 x s
mark me as brainlist answer
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