Question

A car starts from rest and attains a velocity of 72 Km/h in 5 minutes. Calculate the
(a) acceleration (b) distance travelled by the car.

Answer 1

Change speed in M/s

72 into 5/18 is equal to 20 M/s

Time in sec 5min is equal to 5 into 60 equal 300 sec

V equal u+at

20 equal 0+a into 300

a equal 20/300

a equal 1/15 M/s2

V square equal u square +2as

400 equal 0+2 into 1/15 intos

s equal 400 into 15/2

S equal 3000m or 3 km