Question

a car starts from rest and covers a distance of 100 m in one second with uniform accelaeration ,then its accleration is​

Answer 1

.........................

Answer 2

Given :

• Initial velocity, u = 0 m/s

• Time, t = 1 second

• Distance, s = 100 m

To find :

• Acceleration, a

According to the question,

By using Newtons second equation of motion,

➞ s = ut + ½ at²

Where,

• s = Distance
• a = Acceleration
• u = Initial velocity
• t = Time

➞ Substituting the values,

➞ 100 = 0 × 1 + ½ × a × 1 × 1

➞ 100 = 0 + ½ a

➞ 100 - 0 = ½ a

➞ 100 = ½ a

➞ 200 = a

So,the acceleration is 200 m/s².

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More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as