Question

A car starts from rest and enquires a velocity of 54 kmph at 6 seconds. Find the acceleration and distance travelled by a car during this time​

Answer 1

Explanation:

Initial velocity = 0 m/s

Final Velocity = 54 km/h

= 54 × 1000 / 3600

= 15 m/s

v = u + at

15 = 0 + a × 6

a = 15/6

a = 2.5 m/ s^2

s = ut + 1/2 at^2

$s \: = \frac{1}{2} \times \frac{5}{2} \times 36 \\ s = 45m$