Question

A car starts from rest and goes down with a constant acceleration 5m/s^2. After 5s the car reaches bottom of the hill. Its speed at the bottom of the hill, in meters per second, is:​

Answer 1

Explanation:

If we neglect the acceleration g then it would be  25 m/s and if you want it with g then will have to specify the angle of inclination of hill with sun.

Answer 2

Answer:

25 M/SEC

Explanation:

as from rest so

U = 0

T(given)  = 5sec

A = 5 m sec ^-2

..........

by

v = u + at

v = 25 m/sec