A car starts from rest and has an acceleration a=t. A truck is moving with a uniform velocity of 6m/s. At what distance will the car overtake the truck?(at t=0 both start their motion in the same direction from the same position) (1)36m. (2)8m. (3)32m. (4)4m.
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Explanation:
At the moment when the car will be overtaking the truck their velocitis will be same.
so suppose after t second from the start of the motion the car overtake the truck then the velocity of the car at that moment will be v=0+at=t×1m/s
2
=t m/s
and the velocity of the truck at that moment will be u=6m/s(constant)
both should be same i.e u=v or 6=t or t=6 second
so the distance covered by truck oe car because both will be at same place ast that point of time in this time
will be s=vt=6×6=36meter
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