Question

A car starts from rest and has uniform acceleration of 10 m/s2 . After some time it possess the velocity of 30 m/s. The distance covered by the car during this time is A. 920 m. B. 880 m. C. 50 m. D. 45 m.​

Answer 1

Answer:

Answer is 86 sec.

Explanation:

V=at

⇒8=a10

⇒a=0.8m/s

2

V

2

=U

2

+2as

⇒U=8

2

+2×a64

⇒a=

2×64

−64

=−0.5m/s

2

Distance travelled= Area of graph

⇒584=

2

1

×10×8+8×t

1

+

2

1

×16×8

⇒584=40+8t

1

+64

⇒8t

1

=480

⇒t

1

=60

Total time= 10+60+16=86s