A car starts from rest and move along the x axis with constant accelaration 5ms(-2) for 8 seconds. If it than continous with constant velocity,what distance will the car covers in 12 seconds since it started from the rest.Explain
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HERE IS UR ANSWER
As it starts from rest
v = ?
u = 0
a = 5 m/s^2
t = 8 s
we know
v = u + at
v = 0 + 5× 8
v = 40 m/s
now distance covered in 8 second
s = u t + 1/2 a t ^2
s=1 / 2at^2 = 160m.
distance covered in the last 4 sec=const.
speed*time=40m/s*4=160m
total distance covered in 12 sec=160+160=320m ans.
ans=320m
HOPE HELPED
#@®¥@n#
:-)
HERE IS UR ANSWER
As it starts from rest
v = ?
u = 0
a = 5 m/s^2
t = 8 s
we know
v = u + at
v = 0 + 5× 8
v = 40 m/s
now distance covered in 8 second
s = u t + 1/2 a t ^2
s=1 / 2at^2 = 160m.
distance covered in the last 4 sec=const.
speed*time=40m/s*4=160m
total distance covered in 12 sec=160+160=320m ans.
ans=320m
HOPE HELPED
#@®¥@n#
:-)
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