Question

A car starts from rest and moves along a staright line with constant acceleration of 5m/seconds for 10 seconds,then it moves with constant velocity.Calculate the distance trveled by car in 15 seconds after start.

Answer 1

Heya!!Here is your answer friend ⤵⤵

Given that ,

U=0 ( as it starts from rest )

A= 5ms-2

T= 10 seconds


Using first equation of motion,


V=U + AT

V=0+50

V=50 ms-2

Now using second equation of motion,

S= UT + 1/2 AT^2

S= 0*15+1/2 * 5*(15)(15)

S=1/2*5*225

S=562.5m

Hope it helps you ✌✌

Answer 2

U=o
V=5m/s
T=10s
So,a=u+v/t
=0-5/10
=5/10
=0.5m/s^2
Hence, distance travelled in first 15 seconds
= ut+1/2at^2
=0×15+1/2×0.5×15×15
=56.25m,is the answer
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