Question

A car starts from rest and moves along straight road with constant
acceleration of 5 m/s2 for 8 seconds. What distance will the car
cover in 12 sec. since it stated from rest?​

Answer 1

Answer:

320m

Explanation:

v=u+at

v=0+5m/s^2*8

v=40m/s

constant velocity=40m/s

distance covered in the first 8 sec = S=1/2a*t^2=160m.

distance covered in the last 4 sec=const. speed*time=40m/s*4=160m

total distance covered in 12 sec=160+160=320m ans.

ans=320m