A car starts from rest and moves along the x-axis with constant acceleration 5m/s sq. for 8 s. If it then continues with constant velocity. What distance will the car cover in 12 s, since it started from rest.
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Answer:
v = u + at
v = 0 + 5*8
v = 40
v²= u² + 2as
40 = 0 + 2*5s
S = 4m
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