Question

A car starts from rest and moves along the x-axis with constant acceleration 5m/s for 8 seconds if it can continues with constant velocity what distance to the car cover in 12 seconds since it starts from the rest

Answer 1

here 

a = 5m/s²

t = 8 seconds 

u = 0 

v = u + at 

v = at 

v = 5 x 8 = 40 m/s 

when v = constant 

means a = 0 

then distance = velocity x time 

40 x 12 = 480 m