A car starts from rest and moves along the x-axis with constant acceleration 5 m s–2 for 8 seconds. If it then continues with constant velocity, what distances will the car cover in 12 seconds since it started from the rest?
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2
320 m
8 sec with acc.
distance covered=1/2at2
=1/2×5×8×8
=160m
after 8 sec velocity= at =8×5=40
constant velocity for 12-8=4sec
distance covered=v×t
=40×4=160
total distance covered=160+160 =320m
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Answer:
Distance covered in first 8 seconds= ut+ 0.5at^2 + 0+0.5*5*8*8 = 160m
velocity after 8 seconds = u+at = 0+5*8 =40m/s
Distance travelled from 8 to 12 seconds= speed*time =40*4 =160m
Total dist travelled= 160+160=320m
Explanation:
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