Question

a car starts from rest and moves along the x axis with constant acceleration 5ms-2 if then continues with constant velocity what are the distance will the car cover in 12 s since started from​

Answer 1

Answer:

ANSWER

s

1

=ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m

Explanation:

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Answer 2

Here, u=0,a=5m/s2,t=8s

From s=ut+1/2at²

s=0+1/2×5×8²=160m

This is the distance moved by the car is first 8sec. Velocity at the end of 8s is

v=u+at=0+5×8=40m/s.

As this velocity is uniform, distance moved in next 4s

s'=v×t=40×4=160m

Total distance covered by the car in 12s

=s+s'=160+160=320m

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