Question

A car starts from rest and moves along the x - axis with constant acceleration of 5m/s² for 8 seconds if it then continues with constant velocity what distance will the car cover in 12 seconds since it started from the rest ? ​

Answer 1

Answer:

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Explanation:

s 1

=ut+(1/2)at

2 =0+ 21 ×5×8 2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1+s 2

=160+160

=320 m

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Answer 2

Answer:

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s1=ut+(1/2)at2

     =0+21×5×82

     =160 m.

The velocity attained in 8 seconds is given by

v=u+at

   =0+5×8=40 m/s.

The distance traveled in the next 4 seconds is 

s2=40×4=160 m.

So, the total distance traveled by the car is s1+s2=160+160=320 m