Question

a car starts from rest and moves along the x axis with consant acceration 5 m/s ² for 8 seconds .If it continues with consant velocity ,what distance will the car cover in 12 sec since it started from the rest??? pls dont spam..ill mark as brainliest if u ans properly​

Answer 1

Answer:

ANSWER

s

1

=ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m