Question

A car starts from rest and moves along the x-axis with constant acceleration 5 ms-2 for 8 seconds. If
it then continues with constant velocity, what distance will the car cover in 12 seconds since it
started from the rest?
Thorofacit time pranh shows the motion of a cyclist. Find​

Answer 1

V=u+at
v=0+5m/s^2*8
v=40m/s
constant velocity=40m/s
distance covered in the first 8 sec = S=1/2a*t^2=160m.
distance covered in the last 4 sec=const. speed*time=40m/s*4=160m
total distance covered in 12 sec=160+160=320m ans.
ans=320m



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Answer 2

Explanation:

Vo = 0 m/s

a = 5 m/s²

t = 8 s

Vf = Vo + at

Vf = 0 m/s + (5 m/s²)(8 s)

Vf = 40 m/s

what is x at t=12s & Vo = 0 m/s

x = Vf²/2a

x = (40 m/s)²/(2)(5 m/s²)

x = (1600 m²/s²)/10 m/s²

x = 160 m ANSWER