Question

A car starts from rest and moves along the x-axis with
constant acceleration 5 ms*2 for 8 seconds. If it then
continues with constant velocity, what distance will the
car cover in 12 seconds since it started from rest?​

Answer 1

Answer:

A car starts from rest and moves along the x-axis with constant acceleration 5ms-2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest ? v=u+at=0+5×8=40m/s.

Answer 2

☆Answer☆

Distance covered by car in 12 sec since it started from rest is 320 m.

☆Explanation☆

Here,

u = 0

a = 5 m/s²

t = 8s

Now,

s = ut + (1/2)at²

s = 0+(1/2)+5×8²

s = 160 m

This is the distance moved by the car in first 8 seconds.

Velocity at the end of 8s is

v = u + at

v = 0+5×8

v = 40 m/s

As this velocity is uniform, distance moved in next 4s is

s' = v×t

s' = 40×4

s' = 160 m

Total distance by car in 12s is

=> s+s'

=> 160m + 160m

=> 320 m

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