Question

A car starts from rest and moves along the x-axis with constant acceleration 5ms–² for 8 seconds.If it then continues with constant velocity, what distance will they car cover in 12seconds since it started from the rest.?
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Answer 1

$\sf\small\underline\red{Given:-}$

• A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s^2 for 8 seconds.

$\sf\small\underline\red{Find:-}$

• what distance will the car cover in 12 seconds since it started from rest.

$\sf\small\underline\red{Solution:-}$

We know that,

But given that, the initial velocity is zero. Therefore, the distance covered by the car in first 8 seconds is

$\implies s = ut +1/2. at^2$

Therefore, the velocity attained at the end of 8 seconds is:

from,

$\implies s = 0 + 1/2 × 5 × 8^2$

$\implies s = 160 \: meters$

Therefore, since the car has moved with constant velocity from 8th second to 12 second, the distance traveled is

.

$v = u + at$

$\implies v = 0+5×8$

$\implies = 40 m/sec$

Therefore, the total distance traveled is

• 160 + 160 = 320m.

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