A car starts from rest and moves along the x axis with constant acceleration of 5 metre per second square for 8 seconds if then but then continues with the same velocity what distance will the car cover in 12 seconds since it started from rest
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Answer:
320 m
The distance travelled in first eight seconds =x
1
=0+
2
1
∗5∗8
2
=160 m
At this point the velocity v=u+at=0+5×8=40 ms
−1
Therefore, the distance covered in last four seconds, x
2
=40×4=160m
Thus, the total distance x=x
1
+x
2
=160+160=320m
Explanation:
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