Physics, asked by bhavsardhruvn12, 1 month ago

A car starts from rest and moves along the x-axis with constant acceleration 5 ms-2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?​

Answers

Answered by dnyaneshwarkharat333
1

Answer:

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Explanation:

A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds. If it then continues with constant velocity what distance will the car cover in 12 seconds since it started from rest? s = v × t = 40 × 4 = 160 m .

Answered by sanketp21
1

Answer:

Correct option is

A

320 m

s

1

=ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m

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