Question

A car starts from rest and moves along the x-axis with constant acceleration 5 m/s2 for

8 seconds. If it then continues with constant velocity, what distance will the car cover in

12 seconds since it started from the rest?

Answer 1

speed after 8 sec
v=u+at
=5×8
=40m/s

Now
distance covered in 8 s
s=ut+1/2at^2
=1/2 × 5 × 64
=160m
Distance covered by constant speed=40×4=160m
total distance=160+160=320m

Answer 2

Answer:

v=u+at

=5×8

=40m/s

distance travelled in 8 sec

s=ut+1/2at^2

s=1/2×5×64

s=160m

distance travelled in 4 sec

40×4=160m

total distance = 160+160=320m