Question

A car starts from rest and moves along the x-axis with constant acceleration of 5 metre per second square for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest.​

Answer 1

Answer:

A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds. If it then continues with constant velocity what distance will the car cover in 12 seconds since it started from rest? s = v × t = 40 × 4 = 160 m .

Answer 2

Answer:

$\huge \mathbb \purple{QUESTION}$

A car starts from rest and moves along the x-axis with constant acceleration of 5 metre per second square for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest.

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$\huge{\underline{\underline{\mathfrak \purple{Answer}}}}$

For the journey with constant acceleration, the distance travelled = ut+ at²/2

= 5×8²/2 = 160 m

u = 0 m/s, because the car starts from rest.

Now let us calculate the velocity after these 8 seconds.

v= u +at = 5×8 = 40m/s

Since 8 seconds are spent with constant acceleration, the rest 4 seconds from the 12 seconds are spent with constant velocity.

Now, the distance covered by the car with this constant velocity after seconds

$\implies{\tt{speed ×time}}$

$\implies{\tt{40 × 4}}$

$\boxed{\implies{\tt{ 160m}}}$

Hence, total distance covered

$\implies{\tt{160 + 160}}$

$\boxed{\implies{\tt{ 320m}}}$

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