Question

A car starts from rest and moves along the x axis with constant acceleration 5ms for 8seconds.if it then continues with constant velocity,what distance will the car cover in 12seconds since it started from the rest?

Answer 1

make this as brainliest answer .pls

Answer 2

solution:

Here,
u = 0 m/s
a = 5m/s^2 for 8 seconds

So, distance traveled in 8 second

s = ut + 1/at^2

s = 1/2 × 5 × 64

s = 160 m

Now, final velocity at 8 second

As, v = u + at

v = 0 + 5× 8

v = 40 m/s

Now using , S = vt [ acceleration is 0]

s2 = 40 × 4 [ remaining time = 4 second]
s2 = 160 m

Total distance traveled = s1 + s2 = (160 + 160)m = 320 m

____________
Amrit⭐