Question

A car starts from rest and moves along the x axis with a constant acceleration of 5m/s for 8 seconds. If it then continues with uniform velocity find the the distance covered by the car from start to end in 12 seconds

Answer 1

Distance( S ) = u t + 1 / 2 a t ^ 2
u = 0
a = 5 m /s ^ 2
t = 8 seconds
a = v - u / t
5 = v - 0 / 8
v = 40 m /s
v = u for case 2
u = 40 m / s
s = u t + 1 / 2 at ^ 2
s = 40 x 12 + 1 / 2 x 5 x 12 x 12
s = 480 + 360
s = 840m
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