Question

a car starts from rest and moves along the x-axis with the context of the acceleration 5ms-2
for 8 seconds if it continues with a constant velocity what is the distance will the car cover in 12 seconds since it started from the rest​

Answer 1

Answer:

sorry I don't know hey fcvhbvghgfukcgv

Explanation:

sorry

Answer 2

Answer:

320 m.

Explanation:

distance

for first part of the journey = at²/2 = 5x8²/2= 160 m.

for second part of the journey = 40 x 4 = 160m.

total distance = 320 m.