Question

A car starts from rest and moves along x axis with constant acceleration 5m per sec square for 8 sec. if it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest ​

Answer 1

Answer:

s1=ut+(1/2)at2

     =0+21×5×82

     =160 m.

The velocity attained in 8 seconds is given by

v=u+at

   =0+5×8=40 m/s.

The distance traveled in the next 4 seconds is 

s2=40×4=160 m.

So, the total distance traveled by the car is s1+s2=160+160=320 m