A car starts from rest and moves with a constant acceleration. During the 5th second of its motion it covers a distance of 36m. Calculate accelerationof the car and the total distance covered by the car during this time
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GIVEN
u= 0m/s
t= 5s
s= 36m
We can apply
S= ut + 1/2 at^2
➡️ 36 = 0 x 5 + 1/2 x a x (5)^2
➡️ 36 = 25a/2
➡️ 72/25 m/s2 = a
➡️ 2.88 m/s2 = a
So. Answer is 2.88 metre per second squared
I think u have already given the total distance covered by the car in 5 seconds
HOPE THIS HELPS YOU
u= 0m/s
t= 5s
s= 36m
We can apply
S= ut + 1/2 at^2
➡️ 36 = 0 x 5 + 1/2 x a x (5)^2
➡️ 36 = 25a/2
➡️ 72/25 m/s2 = a
➡️ 2.88 m/s2 = a
So. Answer is 2.88 metre per second squared
I think u have already given the total distance covered by the car in 5 seconds
HOPE THIS HELPS YOU
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