Question

A car starts from rest and moves with constant acceleration . during 4th second of it's motion it coverers a distance of 21 m . the acceleration of the car is???? ​

Answer 1

$\huge{\sf{\underline{\overline{\mid{Solution:-}\mid}}}}$

${\underline{\underline{\mathfrak{\star{Given:-}}}}}$

•Initial velocity (u):- 0 m/s

•time(t) :- 4s

•distance(s):- 21 m

${\underline{\underline{\mathfrak{\star{To\:Find:-}}}}}$

• Acceleration (a):- ???

${\underline{\underline{\mathfrak{\star{Applying\: Formula:-}}}}}$

${ \boxed{ \bf{s = ut + \frac{1}{2} at {}^{2} }}}$

$21 = 0 \times 4 + \frac{1}{2} a4 {}^{2} \\ \\ 21 = 0 + \frac{1} {\cancel{2}} a \cancel16 \\ \\ 21 = 8a \\ \\ a = \frac{21}{8} \\ \\ a = 2.6$

$\huge{\underline{\overline{\sf{\mid{Answer:-}\mid}}}}$

${ \boxed{ \bf{a = 2.6 \: ms {}^{ - 2}}}}$