a car starts from rest and moves with constant acceleration .the ratio of distance covered by the car in nth second to that covered in n second is
Answers
Given :
- Initial velocity (u) = 0 m/s
- Acceleration = a (constant)
To Find :
- Ratio of distance covered in nth second to that distance covered in n seconds.
Solution :
We're given that initial velocity is 0 m/s as the car starts from rest and accelerates constantly. So,
Use formula for distance travelled in nth second
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Now, use 2nd equation of motion :
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Dividing 2 by 1
GIVEN :
- Car starts from rest
- Acceleration = Constant
TO FIND :
- RATIO OF DISTANCE COVERED IN nth SECOND AND TO THAT COVERED IN n SECOND.
SOLUTION :
Here initial speed (u) = 0
Acceleration (a) = a m/s²
We know that,
Distance covered in nth second :
→ S(nth) = u + ½ a(2n - 1)
→ S(nth) = 0 + ½ a (2n - 1)
→ S(nth) = ½ a(2n - 1). ...(i)
Now using 2nd equation of motion to find distance covered in n seconds :
→ S(n) = ut + ½ at²
→ S(n) = 0 × n + ½ a × n²
→ S(n) = ½ an². ....(ii)
Now finding ratio :
→ S(nth) : S(n) = ½a(2n - 1) : (½ an²)
→ S(nth) : S(n) = ½ a(2n - 1)/ ½ an²
→ S(nth) : S(n) = (2n - 1) : n²
∴ Ratio of distance covered in nth second to that of distance covered in n second = (2n - 1) : n²