Question

a car starts from rest and moves with constant acceleration of 5m/s^2 for 8 seconds.calculate the final velocity and distance covered.​

Answer 1

Explanation:

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Answer 2

Answer:

320m

s1 =ut+(1/2)at ^2

=0+ 1/2×5×8 ^2.

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s2= 40×4=160 m.

So, the total distance traveled by the car is

S1 + S 2 =160+160=320 m

hope you would understand my answer ..