Question

A car starts from rest and moves with constant acceleration. During 4th second of its motion it covers a distance of 21 meters. The acceleration of the car is:
A. 04
B. 06
C. 08
D. 16

Right answer is B.

Data: vi=0, t=4th second, d=21 m, a=?
Solution: d=vit+1/2a(2n-1)
21=0+1/2a(2(4)-1)
21=0+1/2a(8-1)
21=0+1/2a(7)
(21×2)/7=a
42/7=a
6=a
I have already written the right answer so Don't write wrong answer. Just rewrite the right answer and make ur answer brainliest. ​

Answer 1

Answer:

Here is your answer

Explanation:

PLEASE MARK ME AS THE BRAINLIEST

Answer 2

Answer:

Right answer is B.

Data: vi=0, t=4th second, d=21 m, a=?

Solution: d=vit+1/2a(2n-1)

21=0+1/2a(2(4)-1)

21=0+1/2a(8-1)

21=0+1/2a(7)

(21×2)/7=a

42/7=a

6=a