Question

a car starts from rest and moves with constant acceleration. the ratio of the distance covered in the nth sec to that of the distance covered in n seconds is

Answer 1

Answer:

the Answer for your question is↓↓↓

The car starts from rest, so initial velocity = 0

Distance travelled = 400 m

Time taken = 20 s

We know the equation of motion, S = ut + ½ at2

400 = 0 + ½ a * (20)2

a = 2 m/s2

Now, mass = 7 metric tonnes

= 7 * 1000

= 7000 kg

So force = mass * acceleration

F = 7000 *

Answer 2

Refer the attachment

Thank my answer and do follow..