Question

A car starts from rest and moves with constant acceleration the ratio of the distance covered in nth second to distance covered in n
seconds is​

Answer 1

Answer:

distance traveled by a car is 'n' th second is

sn = u+ a/2(2n-1)

distance travelled in 'n' second is

s= un +1/2 an2

here u is zero,since car start from rest

then, sn/s = a/2 (2n-1)/1/2an2

therefore,the ratio = sn/s = 2/n -1/n2

Explanation:

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