Question

A car starts from rest and moves with uniform acceleration of 4/s^ in a straight line . what is the velocity after 8seconds

Answer 1

Final Answer:-

$v=32m/s$

Formula Used:-

$v=u+at$

Given:-

$u(initial\:velocity)=0m/s\\a(acceleration)=4m/s\\t(time)=8s$

To Find:-

the velocity after 8 seconds

Solution:-

car starts from rest means initial velocity $(u)=0m/s$

moves with uniform acceleration $(a)=4m/s$

∴ velocity after 8 seconds:-

by using $v=u+at$

$v=0+4*8$ [← putted values in equation]

$v=0+32$

$v=32m/s$

hence, velocity after 8 seconds ⇒ $24 m/s$

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here,

$v(final \:velocity)=32m/s\\u(initial\:velocity)=0m/s\\a(acceleration)=4m/s\\t(time)=8s$

note:-

it's not necessary that you also use the same formula/method to get correct answer .

Answer 2

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