Question

A car starts from rest and moves with uniform acceleration 'a'. At the same instant from the same point a bike crosses with uniform velocity 'u'. When and where will they meet? What is the velocity of car with respect to the bike at the time of meeting?

Answer 1

Answer:

Explanation:

Step-by-step explanation:

let car and bike meet 'd' from starting point each other and after time 't' they meet.

as car start from rest u = 0

so

s= ut +1/2 at²

2d = at² - - - -- - - 1

for bike is in uniform speed

so

distance = sppeed *time

d = u*t - - -- - - 2

from eq 1 and 2

2ut = at²

t = 2u / a

so distance

d = u* 2u/ a

= 2u² / a

so bike and car meet at 2u² / a distance after t = 2u / a time.