a car starts from rest and moving along the x axis with constant acceleration 5m/s² for 8 sec . if it then continue with constant velocity, what distance will the car cover in 12 second since it started from the rest.
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For the first part we'll use
S=ut+½at²
=>s=0×8+½×5×8²
=160 m. -(i)
Second part
v²=u²+2as
V²=0+1600
V=40
Now we know the final v so we'll calculate distance for the 2nd part
s=vt
=40×4(time for part II)
=160m. -(ii)
Adding i and ii
320m
And. 320m
S=ut+½at²
=>s=0×8+½×5×8²
=160 m. -(i)
Second part
v²=u²+2as
V²=0+1600
V=40
Now we know the final v so we'll calculate distance for the 2nd part
s=vt
=40×4(time for part II)
=160m. -(ii)
Adding i and ii
320m
And. 320m
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