A car starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3 seconds. What is his acceleration.
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Answered by
1
acceleration=v-u/t
6-0/3
6/3
a=2
6-0/3
6/3
a=2
shubhamchhikara:
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Answered by
1
Acceleration= v-u/t
where , v is the final velocity
u is the initial velocity
t is the time taken
therefore, acceleration = 6-0/3
= 2 m/s^2
where , v is the final velocity
u is the initial velocity
t is the time taken
therefore, acceleration = 6-0/3
= 2 m/s^2
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