Question

A car starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 800m in 10 seconds.find the acceleration

Answer 1

We know that s = ut + 1/2 at^2

                        800 = 0 + 1/2 * a * (10)^2

                        800 = 1/2 * a * 100

                       800 = 50a

                        a = 16m/s^2.


Hpe this helps!

Answer 2

➪ Acceleration of car = 16 m/s²

Explanation:

Given:

• A car starts from rest (u) = 0
• Distance covered by car (s) = 800m
• Time taken by car (t) = 10 seconds

To Find:

• What is the acceleration (a) = ?

Formula to be used:

• S = ut + 1/2at²

Solution: By using Newton's second law of motion we can find the acceleration of the car

$\implies{\rm }$ S = ut + 1/2at²

$\implies{\rm }$ 800 = 0 x 10 + 1/2 x a x (10)²

$\implies{\rm }$ 800 = 0 + 1/2 x a x 100

$\implies{\rm }$ 800 = 0 + 50 x a

$\implies{\rm }$ 800 = 50a

$\implies{\rm }$ 800/50 = a

$\implies{\rm }$ 16 m/s² = a

Hence, The acceleration of the car is 16 m/s²

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★ Other laws of motion are ★

• v = u + at
• v² = u² + 2as