A car starts from rest and rolls down a hill with constant accelration if it travels a distance of 800 metre in 10 seconds
Answers
Answered by
3
We know that,
S = ut + 1/2 at^2
800 = 0 + 1/2 * a * (10)^2
800 = 0 + 1/2 a * 100
800 = 50a
a = 800/50
= 16 m/s^2.
Hope this helps!
S = ut + 1/2 at^2
800 = 0 + 1/2 * a * (10)^2
800 = 0 + 1/2 a * 100
800 = 50a
a = 800/50
= 16 m/s^2.
Hope this helps!
Answered by
2
here ,
s = 800 m
u = 0 m/s
t = 10 seconds
s = ut + 1/2 at ²
= 0 + 1/2 at²
= 1/2 x a x 10 x 10
800 = 100a/2
800 = 50 a
16 = a
so , a = 16 m/s²
v = u + at
v = 0 + 16 x 10
v = 160 m/s
s = 800 m
u = 0 m/s
t = 10 seconds
s = ut + 1/2 at ²
= 0 + 1/2 at²
= 1/2 x a x 10 x 10
800 = 100a/2
800 = 50 a
16 = a
so , a = 16 m/s²
v = u + at
v = 0 + 16 x 10
v = 160 m/s
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