Question

A car starts from rest and rolls down a hill with constant acceleration. It travels a distance f 500m in 20 secs. Calculate its acceleration

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 (As car starts from rest)

Distance traveled, s = 500 m

Time taken, t = 20 seconds

To Calculate,

Acceleration, a = ?

According to 2nd equation of motion,

we know that,

s = ut + 1/2at²

so, putting all the values, we get

s = ut + 1/2at²

⇒ 500 = 0 × 20 + 1/2 × a × 20²

⇒ 500 = 1/2 + a × 400

⇒ 500 = 200a

⇒ 500/200 = a

⇒ a = 2.5 m/s²

Hence. the acceleration by car is 2.5 m/s².

Answer 2

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Question :-

⋄ A car starts from rest and rolls down a hill with constant acceleration. It travels a distance f 500m in 20 secs. Calculate its acceleration.

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Given :-

• Initial velocity (u) =0m/s
• Time taken (t) =20s
• Distance covered (s) =500m

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To Find:-

• Acceleration of the car.

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Solution :-

By using 2nd equation of motion

s =ut+1/2at²

500=0×20 +1/2×a× 20²

500= 1/2 ×a ×400

a= 500/200

a=2.5m/s²

∴ The acceleration of the car is 2.5m/s².

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Some Equation of motion are:-

$v = u + at$

$s = ut + \frac{1}{2} at {}^{2}$

$v {}^{2} = u {}^{2} + 2as$

here,

v is the final velocity

u is the initial velocity

t is the time taken

s is the distance covered

a is the acceleration