Question

A car starts from rest and travels some distance in 5 seconds and acceleration 12 ml's
and force acting on the car is 14400 N. Find mass of the car and distance travelled?
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Answer 1

Gɪᴠᴇɴ :-

• Initial velocity (u) = 0 m/s --(At rest)
• Time taken (t) = 5 seconds
• Acceleration (a) = 12 m/s²
• Force (F) = 14400 N

ᴛᴏ ғɪɴᴅ :-

• Final velocity (v)
• Mass(m)
• Distance travelled (s)

sᴏʟᴜᴛɪᴏɴ :-

On using (1) equation of motion, we get,

➦ v = u + at

➭ v = 0 + 12 × 5

➭ v = 60 m/s

Hence,

• Final velocity (v) = 60 m/s

Now,

On applying third equation of motion, we get,

➦ v² - u² = 2as

➭ (60)² - (0)² = 2×12 × s

➭ 3600 = 24s

➭ s = 3600/24

➭ s = 150 m

Hence,

• Distance travelled (s) = 150 m

Now,

We know that,

➦ Force (F) = Mass (m) × Acceleration (a)

➦ F = ma

➭ 14400 = m × 12

➭ 12m = 14400

➭ m = 14400/12

➭ m = 1200 kg

Hence,

• Mass (m) = 1200 kg

Therefore,

• Distance travelled (s) = 150 m
• Mass (m) = 1200 kg