Question

A car starts from rest and travels with a velocity of 60m/sec for 8 seconds. Find the acceleration of the car.

Answer 1

 Units are ignored in calculation.

Answer:

7.5 m/s^2

Explanation:

We know acceleration defines the rate of  change in velocity( with respect to time ).

  Mathematically, acceleration = ( final velocity - initial velocity ) / time

Here car was initially at rest which means initial velocity of the body is 0.

After 8 sec, velocity of the body becomes 60 m/s. So, consideration of this situation says final velocity to be 60 m/s.

Thus,

 Acceleration = ( 60 - 0 ) / 8

                   = 60 / 8

                   = 30 / 4 = 15 / 2

                   = 7.5

Answer 2

Answer:

$7.5 \ m/s^{2}$

Explanation:

Given:

• Initial velocity = u = 0 m/s (As the car starts from rest)

• Final velocity = v = 60 m/s
• Time = t = 8 seconds

To find:

• Acceleration of the car (a)

Using the first equation of motion which says:

V=u+at

Where:

V=final velocity

u=Initial velocity

a=Acceleration

t=Time

Substituting the values:

60=0+a×8

60=8a

a = $\frac{60}{8}$

a = $7.5 \ m/s^{2}$

The acceleration of the car is equal to 7.5 m/s²

More:

Second equation of motion = $S=ut+ \frac{1}{2} at^{2}$

Third equation of motion = $V^{2} -U^{2} =2as$