Question

A car starts from rest and travels with uniform acceleration “a” for some time and
then with uniform retardation “B”and comes to rest. The time of motion is “p”. Find
the maximum velocity attained by it. ​

Answer 1

The right option is B

We have,

Acceleration =a

Retardation =b

Let t and t ′ the time of acceleration And retardation respectively.

Let v be the maximum velocity.

Therefore,

t+t′ =T

since v/t =a and \dfrac{v}{t'}=b$$

So, t+t′= v/a + v/b=T

(a+b)v/ab =T

Therefore,

v= tab/a+b

I hope you understood