Question

A car starts from rest and travels with uniform acceleration for some time and then with uniform retardation b and comes to rest. If the total time of travel of the car is 't', the maximum velocity attained by it is v and total S displacement S then S/V=
A t/2
B 2t
C t^2
D t​

Answer 1

Answer:

let initial distance traveled by the car is s

1

, in time t

1

, and velocity is v

1

then

s

1

=

2

1

αt

1

2

v

1

=αt

1

v

1

2

=2αs

1

let remaining distance traveled by the car is s

2

, in time t

2

, and velocity is v

2

then

Now, u

2

=v

1

So, s

2

=v

1

t

2

−

2

1

βt

2

2

v

2

=0=αt

1

−βt

2

⇒

t

2

t

1

=

α

β

t

1

+t

2

=t⇒t

2

(

α

β

+1)=t⇒t

2

=

β+α

αt

So, t

1

=(

β+α

βt

)

Clearly maximum velocity attained is v

1

, so

v

1

=αt

1

=(

β+α

αβt

)