Question

A car starts from rest and travels with uniform acceleration 'α' for some time and then with uniform retardation 'β' and comes to rest. The time of motion is 't' . Find the maximum velocity attained by it.(αβt/(α+β))

Answer 1

v=u+at

since u=0

v=at

and t=v/a

in such case a=\frac{\alpha+\beta}{\alpha*\beta} [/tex]

so v=(alpha=beta)*t/alpha*beta

Answer 2

Answer:ABT²/2(A+B)

Explanation:

Hope it helps u