A car starts from rest attains a velocity of 36km/h with an acceleration of 0.2m/s
prem33:
friend what have to find
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Answered by
6
time =x.
36 km /hr into m/s v=10m/s u= 0
36×5/18=10m/s
10/x=1/5 used formula=(v-u)/t
x=50 sec
for distance =
v^2-u2=2as where a = acc. and s = distance
100=2×1/5×s
s=250m
36 km /hr into m/s v=10m/s u= 0
36×5/18=10m/s
10/x=1/5 used formula=(v-u)/t
x=50 sec
for distance =
v^2-u2=2as where a = acc. and s = distance
100=2×1/5×s
s=250m
Answered by
6
u=0
v=10m/s
a=0.2m/s^2
10=0+0.2×t
10/0.2=t
50s =t (time)
100=0 +2×0.2×s
100=0.4s
250=s (distance)
hope it will help you !
v=10m/s
a=0.2m/s^2
10=0+0.2×t
10/0.2=t
50s =t (time)
100=0 +2×0.2×s
100=0.4s
250=s (distance)
hope it will help you !
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