Question

a car starts from rest attains velocity of 54km/h in 3 min find acceleration and distance travelled for attaning this velocity

Answer 1

u=0 , v=54km/h = 15m/s ,t=3 min = 3×60= 180sec.
Now , a= v-u / t = 15-0 /180 = 15/180 m/s^2

Answer 2

HELLO FRIEND HERE IS YOUR ANSWER !!

Given -  Speed/velocity = 54km/hr

= converting it into m/s

= 54*5/18

=15m/s.

time= 3 minutes = 3*60

= 180 seconds.

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to find- a] Acceleration.

b] Distance travelled.

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CALCULATION

car starts from rest so, u=0.

a= v-u/t

= 15-0/180

= 15/180= 1/12

= 1/12 m/s^2

distance = speed * time

= 15*180

= 2800 m.