Question

A car starts from rest. If its acceleration is 1.5 m/s2 in 1.5 seconds, then calculate th distance travelled by it.​

Answer 1

Answer:

1.6875 M

Step-by-step explanation:

Here, we are given that,

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 s

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,Distance (s) = ?

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,Distance (s) = ?By using the second equation of motion,

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,Distance (s) = ?By using the second equation of motion,★ s = ut + ½at²

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,Distance (s) = ?By using the second equation of motion,★ s = ut + ½at²s is distance

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,Distance (s) = ?By using the second equation of motion,★ s = ut + ½at²s is distanceu is initial velocity

Here, we are given that,Initial velocity (u) = 0 (as it starts from rest)Acceleration (a) = 1.5 m/s²Time taken (t) = 1.5 sThen,Distance (s) = ?By using the second equation of motion,★ s = ut + ½at²s is distanceu is initial velocityt is time

a is acceleration

a is acceleration⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²

a is acceleration⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²⇒ s = ½ × 1.5 × 2.25

a is acceleration⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 1.5 × 2.25

a is acceleration⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 3.375

a is acceleration⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 3.375⇒ s = 1.6875 m

a is acceleration⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 1.5 × 2.25⇒ s = ½ × 3.375⇒ s = 1.6875 m∴ Distance travelled by it is 1.6875 m.

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Answer 2

Answer:

2•25 km distance

Step-by-step explanation:

d=s×t

d=1•5×1•5

d=2•25